Relation between Taper Angle and Amount of Yarn on a Beam:
Let,
s = Traverse length.
L = Axial
d = Empty beam dia.
D = Full beam dia.
dm = (D+d)/2 = mean dia.
Where,
X = Tape distance
α = Taper angle
v = Volume of yarn stored on beam.
Let, s > x so as to maintain stability
∏D2L ∏d2L
V = ………. - ………….
4 4
∏L
= …….. (D2 – d2)
4
D+d D-d
= ∏L (…….) (……..)
2 2
From figure, it is clear that
D+d D-d
dm = ……. & ………. = x tan α
2 2
So, v = π L dm (x tanα)
V > π L dm S tan α if, x > s
V < π L dm S tan α if, x < s
So, V ∞ S tan α if α = 90° then V = α
So unlimited amount of yarns can be wound if flange stays perpendicular to beam barrel. Practically this is impossible. But this type of package permit’s to wind high amount of yarn.